sesquitertius: Difference between revisions
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|georg=sēsqui-[[tertius]], a, um = επίτριτος, bezeichnet das [[Verhältnis]] [[von]] 4 zu 3, [[also]] 1 + <sup>1</sup>/<[[sub]]>3</[[sub]]> : 1, d.h. <sup>4</sup>/<[[sub]]>3</[[sub]]> :<sup> 3</sup>/<[[sub]]>3</[[sub]]>, Cic. Tim. 23. Boëth. inst. arithm. 1, 1 u. 1, 24 u.a. Arnob. 2. no. 24 (wo sesquetertius). | |georg=sēsqui-[[tertius]], a, um = επίτριτος, bezeichnet das [[Verhältnis]] [[von]] 4 zu 3, [[also]] 1 + <sup>1</sup>/<[[sub]]>3</[[sub]]> : 1, d.h. <sup>4</sup>/<[[sub]]>3</[[sub]]> :<sup> 3</sup>/<[[sub]]>3</[[sub]]>, Cic. Tim. 23. Boëth. inst. arithm. 1, 1 u. 1, 24 u.a. Arnob. 2. no. 24 (wo sesquetertius). | ||
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{{LaEn | |||
|lnetxt=sesquitertius sesquitertia, sesquitertium ADJ :: containing 4/3 of anything | |||
}} | }} | ||
Revision as of 06:35, 28 February 2019
Latin > English (Lewis & Short)
sesquĭ-tertĭus: a, um, num. adj., corresp. to the Gr. ἐπίτριτος,
I containing one and a third, or four thirds; bearing the ratio of four to three: intervallum, Cic. Univ. 7, 21; cf. sesquioctavus, and v. sesqui.
Latin > French (Gaffiot 2016)
sēsquĭtertĭus, a, um, qui contient une fois et un tiers [= 4/3] : Cic. Tim. 21.
Latin > German (Georges)
sēsqui-tertius, a, um = επίτριτος, bezeichnet das Verhältnis von 4 zu 3, also 1 + 1/<sub>3</sub> : 1, d.h. 4/<sub>3</sub> : 3/<sub>3</sub>, Cic. Tim. 23. Boëth. inst. arithm. 1, 1 u. 1, 24 u.a. Arnob. 2. no. 24 (wo sesquetertius).
Latin > English
sesquitertius sesquitertia, sesquitertium ADJ :: containing 4/3 of anything
