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τετράγωνος: Difference between revisions
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|mdlsjtxt=τετρά-˘γωνος, ον, [[γωνία]]<br /><b class="num">I.</b> with [[four]] [[equal]] angles, rectangular or [[square]], Lat. [[quadratus]], Hdt.; δοκοί τ. squared beams, Thuc.:— τετράγωνον, ου, a [[square]], Plat.: a [[body]] of men [[drawn]] up in [[square]], Lat. [[agmen]] [[quadratum]], Xen.<br /><b class="num">2.</b> τ. [[ἀριθμός]] a [[square]] [[number]], i. e. a [[number]] multiplied [[into]] itself, Plat.<br /><b class="num">II.</b> metaph. [[square]], i. e. [[perfect]], [[Simon]]. ap. Plat. | |mdlsjtxt=τετρά-˘γωνος, ον, [[γωνία]]<br /><b class="num">I.</b> with [[four]] [[equal]] angles, rectangular or [[square]], Lat. [[quadratus]], Hdt.; δοκοί τ. squared beams, Thuc.:— τετράγωνον, ου, a [[square]], Plat.: a [[body]] of men [[drawn]] up in [[square]], Lat. [[agmen]] [[quadratum]], Xen.<br /><b class="num">2.</b> τ. [[ἀριθμός]] a [[square]] [[number]], i. e. a [[number]] multiplied [[into]] itself, Plat.<br /><b class="num">II.</b> metaph. [[square]], i. e. [[perfect]], [[Simon]]. ap. Plat. | ||
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{{Chinese | |||
|sngr='''原文音譯'''：tetr£gwnoj 帖特拉-哥挪士<p>'''詞類次數'''：形容詞（1）<p>'''原文字根'''：四-角的<p>'''字義溯源'''：四角的，四方的，四邊的；由（[[τέσσαρες]]）*=四）與（[[γωνία]]）*=房角，角落）組成<p/>'''出現次數'''：總共（1）；啓（1）<p/>'''譯字彙編'''：<p>1） 四方的（1） 啓21:16 | |||
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