hydraula: Difference between revisions
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{{Lewis | {{Lewis | ||
|lshtext=<b>hydraula</b>: ae, or hydraules, ae, m., = [[ὑδραύλης]],<br /><b>I</b> one [[who]] plays on the waterorgan, Suet. Ner. 54; Petr. 36; acc. -am, Mart. Cap. 9, § 924. | |lshtext=<b>hydraula</b>: ae, or hydraules, ae, m., = [[ὑδραύλης]],<br /><b>I</b> one [[who]] plays on the waterorgan, Suet. Ner. 54; Petr. 36; acc. -am, Mart. Cap. 9, § 924. | ||
}} | |||
{{Gaffiot | |||
|gf=<b>hўdraula</b> <b>(-lēs)</b>, æ, m. ([[ὑδραύλης]]), celui qui joue de l’orgue hydraulique : Suet. [[Nero]] 54 ; Petr. 36, 6. | |||
}} | |||
{{Georges | |||
|georg=hydraula, s. 1. [[hydraulia]]. | |||
}} | |||
{{LaZh | |||
|lnztxt=*hydraula, ae. f. :: [[水推之磨]]。[[水琴]] | |||
}} | }} | ||
Latest revision as of 19:50, 12 June 2024
Latin > English (Lewis & Short)
hydraula: ae, or hydraules, ae, m., = ὑδραύλης,
I one who plays on the waterorgan, Suet. Ner. 54; Petr. 36; acc. -am, Mart. Cap. 9, § 924.
Latin > French (Gaffiot 2016)
hўdraula (-lēs), æ, m. (ὑδραύλης), celui qui joue de l’orgue hydraulique : Suet. Nero 54 ; Petr. 36, 6.
Latin > German (Georges)
hydraula, s. 1. hydraulia.
