corsair: Difference between revisions

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{{Woodhouse
{{Woodhouse1
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===substantive===
 
[[prose|P.]] and [[verse|V.]] [[λῃστής]], ὁ.
 
[[be a corsair]], v.: [[prose|P.]] [[λῃστεύειν]].
}}
}}

Latest revision as of 19:35, 9 December 2020

English > Greek (Woodhouse)

substantive

P. and V. λῃστής, ὁ.

be a corsair, v.: P. λῃστεύειν.