Ask at the forum if you have an Ancient or Modern Greek query!

amygdalum: Difference between revisions

From LSJ

Τὸ νικᾶν αὐτὸν αὑτὸν πασῶν νικῶν πρώτη τε καὶ ἀρίστη. Τὸ δὲ ἡττᾶσθαι αὐτὸν ὑφ' ἑαυτοῦ πάντων αἴσχιστόν τε ἅμα καὶ κάκιστον. → Τo conquer yourself is the first and best victory of all, while to be conquered by yourself is of all the most shameful as well as evil

Plato, Laws, 626e
m (Text replacement - "]]>" to "]]")
(D_1)
Line 1: Line 1:
{{Lewis
{{Lewis
|lshtext=<b>ămygdălum</b>: i, n., = [[ἀμύγδαλον]], i. q. [[amygdala]].<br /><b>I</b> An almond, an almondkernel, Ov. A. A. 3, 183; Pall. 2, 15 fin.—<br /><b>II</b> An almond-[[tree]], Col. Arb. 25.
|lshtext=<b>ămygdălum</b>: i, n., = [[ἀμύγδαλον]], i. q. [[amygdala]].<br /><b>I</b> An almond, an almondkernel, Ov. A. A. 3, 183; Pall. 2, 15 fin.—<br /><b>II</b> An almond-[[tree]], Col. Arb. 25.
}}
{{Gaffiot
|gf=<b>ămygdălum</b>,¹⁶ ī, n. ([[ἀμύγδαλον]]),<br /><b>1</b> amande : Ov. Ars 3, 183<br /><b>2</b> amandier : Col. Arb. 25, 1.
}}
}}

Revision as of 06:33, 14 August 2017

Latin > English (Lewis & Short)

ămygdălum: i, n., = ἀμύγδαλον, i. q. amygdala.
I An almond, an almondkernel, Ov. A. A. 3, 183; Pall. 2, 15 fin.—
II An almond-tree, Col. Arb. 25.

Latin > French (Gaffiot 2016)

ămygdălum,¹⁶ ī, n. (ἀμύγδαλον),
1 amande : Ov. Ars 3, 183
2 amandier : Col. Arb. 25, 1.