sesquioctavus: Difference between revisions
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|georg=sēsqui-octāvus, a, um = επόγδοος, gibt das [[Verhältnis]] [[von]] 9 zu 8 an, [[also]] 1 + <sup>1</sup>/<[[sub]]>8</[[sub]]> : 1, d.h. <sup>9</sup>/<[[sub]]>8</[[sub]]> : <sup>8</sup>/<[[sub]]>8</[[sub]]>, Cic. Tim. 23 M. Arnob. 2, 24 (wo [[sesqueoctavus]]). Boëth. inst. [[mus]]. 1, 10. p. 197, 20 u.a. | |georg=sēsqui-octāvus, a, um = επόγδοος, gibt das [[Verhältnis]] [[von]] 9 zu 8 an, [[also]] 1 + <sup>1</sup>/<[[sub]]>8</[[sub]]> : 1, d.h. <sup>9</sup>/<[[sub]]>8</[[sub]]> : <sup>8</sup>/<[[sub]]>8</[[sub]]>, Cic. Tim. 23 M. Arnob. 2, 24 (wo [[sesqueoctavus]]). Boëth. inst. [[mus]]. 1, 10. p. 197, 20 u.a. | ||
}} | |||
{{LaEn | |||
|lnetxt=sesquioctavus sesquioctava, sesquioctavum ADJ :: containing 9/8 of a thing | |||
}} | }} | ||
Revision as of 06:20, 28 February 2019
Latin > English (Lewis & Short)
sesquĭ-octāvus: a, um, num. adj., corresp. to the Gr. ἐπόγδοος,
I containing nine eighths, or one and an eighth; bearing the ratio of nine to eight: intervallum, Cic. Univ. 7, 21; cf. sesquitertius, and v. sesqui.
Latin > French (Gaffiot 2016)
sēsquĭoctāvus, a, um, qui contient une fois et un huitième [ou 9/8] : Cic. Tim. 21 || sesquioctavus decimus Boet. Mus. 3, 2, égal aux 19/18.
Latin > German (Georges)
sēsqui-octāvus, a, um = επόγδοος, gibt das Verhältnis von 9 zu 8 an, also 1 + 1/<sub>8</sub> : 1, d.h. 9/<sub>8</sub> : 8/<sub>8</sub>, Cic. Tim. 23 M. Arnob. 2, 24 (wo sesqueoctavus). Boëth. inst. mus. 1, 10. p. 197, 20 u.a.
Latin > English
sesquioctavus sesquioctava, sesquioctavum ADJ :: containing 9/8 of a thing
