ἀδηκότες: Difference between revisions

From LSJ

πῶς δ' οὐκ ἀρίστη; τίς δ' ἐναντιώσεται; τί χρὴ γενέσθαι τὴν ὑπερβεβλημένην γυναῖκα; (Euripides' Alcestis 152-54) → How is she not noblest? Who will deny it? What must a woman have become to surpass her?

Source
m (pape replacement)
m (Text replacement - "(?s)({{elru\n\|elrutext.*}}\n)({{.*}}\n)({{pape.*}})" to "$3 $1$2")
 
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{{bailly
{{bailly
|btext=<i>part. pf. plur. de</i> [[ἀδέω]].
|btext=<i>part. pf. plur. de</i> [[ἀδέω]].
}}
{{pape
|ptext=s. [[ἀδέω]].
}}
}}
{{elru
{{elru
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{{etym
{{etym
|etymtx=Grammatical information: ptc. nom. pl.<br />Meaning: uncertain; in <b class="b3">καμάτῳ ἀδηκότες ἠδε καὶ ὕπνῳ Κ</b> 98 etc.<br />Origin: XX [etym. unknown]<br />Etymology: Connected with [[ἅδην]] or [[ἡδὺς]], i.e. [[ἀαδεῖν]]; see s.v. [[ἄαδα]]. Discussion in DELG.
|etymtx=Grammatical information: ptc. nom. pl.<br />Meaning: uncertain; in <b class="b3">καμάτῳ ἀδηκότες ἠδε καὶ ὕπνῳ Κ</b> 98 etc.<br />Origin: XX [etym. unknown]<br />Etymology: Connected with [[ἅδην]] or [[ἡδὺς]], i.e. [[ἀαδεῖν]]; see s.v. [[ἄαδα]]. Discussion in DELG.
}}
{{pape
|ptext=s. [[ἀδέω]].
}}
}}

Latest revision as of 12:50, 30 November 2022

French (Bailly abrégé)

part. pf. plur. de ἀδέω.

German (Pape)

s. ἀδέω.

Russian (Dvoretsky)

ἀδηκότες: part. pf. pl. к *ἀδέω.

Frisk Etymological English

Grammatical information: ptc. nom. pl.
Meaning: uncertain; in καμάτῳ ἀδηκότες ἠδε καὶ ὕπνῳ Κ 98 etc.
Origin: XX [etym. unknown]
Etymology: Connected with ἅδην or ἡδὺς, i.e. ἀαδεῖν; see s.v. ἄαδα. Discussion in DELG.