ὑπερβήῃ: Difference between revisions
From LSJ
εἰ πλείονα δ' εἰδείης Σισύφου → if you were more intelligent than Sisyphus
m (Text replacement - "<span class="sense"><span class="bld">A<\/span> (?s)(?!.*<span class="bld">)(.*)(<\/span>)(\n}})" to "$1$3") |
m (Text replacement - "(?s)({{ls\n\|lstext.*}}\n)({{bailly.*}}\n)" to "$2$1") |
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|Beta Code=u(perbh/h| | |Beta Code=u(perbh/h| | ||
|Definition=v. [[ὑπερβαίνω]] A. 1.2. | |Definition=v. [[ὑπερβαίνω]] A. 1.2. | ||
}} | |||
{{bailly | |||
|btext=<i>3ᵉ sg. sbj. ao.2 épq. de</i> [[ὑπερβαίνω]]. | |||
}} | }} | ||
{{ls | {{ls | ||
|lstext='''ὑπερβήῃ''': ἴδε [[ὑπερβαίνω]]. | |lstext='''ὑπερβήῃ''': ἴδε [[ὑπερβαίνω]]. | ||
}} | }} | ||
{{Autenrieth | {{Autenrieth | ||
Revision as of 18:20, 2 October 2022
English (LSJ)
v. ὑπερβαίνω A. 1.2.
French (Bailly abrégé)
3ᵉ sg. sbj. ao.2 épq. de ὑπερβαίνω.
Greek (Liddell-Scott)
ὑπερβήῃ: ἴδε ὑπερβαίνω.
English (Autenrieth)
see ὑπερβαίνω.
Greek Monotonic
ὑπερβήῃ: Επικ. γʹ ενικ. υποτ. αορ. βʹ του ὑπερβαίνω.
Russian (Dvoretsky)
ὑπερβήῃ: эп. 3 л. sing. aor. 2 conjct. к ὑπερβαίνω.
