silver-plate: Difference between revisions
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τὰ δὲ πεπερασμένα πεπερασμενάκις ἀνάγκη πεπεράνθαι πάντα → and the product of a finite number of things taken in a finite number of ways must always be finite
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m (Text replacement - "ἐπαργυρόω, περιαργυρόω;" to "ἐπαργυρόω, καταργυρόω, περιαργυρόω;") |
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{{Woodhouse1 | {{Woodhouse1 | ||
|Text=[[File: | |Text=[[File:p2.png|right|Woodhouse page for {{PAGENAME}} - Opens in new window|link={{filepath:woodhouse_776.jpg}}]] | ||
===substantive=== | ===substantive=== | ||
[[prose|P.]] [[ἀργύριον ἄσημον]]. | [[prose|P.]] [[ἀργύριον ἄσημον]]. | ||
}} | |||
{{trml | |||
|trtx====verb=== | |||
Bulgarian: посребрявам; Catalan: argentar, platejar; Dutch: [[verzilveren]]; Finnish: hopeoida; German: [[versilbern]]; Greek: [[ασημώνω]], [[αργυρώνω]], [[επαργυρώνω]], [[κάνω επαργύρωση]]; Ancient Greek: [[ἀργυρόω]], [[διαργυρόω]], [[ἐπαργυρόω]], [[καταργυρόω]], [[περιαργυρόω]]; Italian: [[argentare]]; Polish: posrebrzać; Portuguese: [[argentar]]; Russian: [[серебрить]], [[посеребрить]]; Spanish: [[platear]], [[argentar]] | |||
}} | }} | ||
Latest revision as of 17:15, 31 March 2024
English > Greek (Woodhouse)
substantive
Translations
verb
Bulgarian: посребрявам; Catalan: argentar, platejar; Dutch: verzilveren; Finnish: hopeoida; German: versilbern; Greek: ασημώνω, αργυρώνω, επαργυρώνω, κάνω επαργύρωση; Ancient Greek: ἀργυρόω, διαργυρόω, ἐπαργυρόω, καταργυρόω, περιαργυρόω; Italian: argentare; Polish: posrebrzać; Portuguese: argentar; Russian: серебрить, посеребрить; Spanish: platear, argentar
