ἀμφιετεί: Difference between revisions
From LSJ
Ὁ δὲ μὴ δυνάμενος κοινωνεῖν ἢ μηδὲν δεόμενος δι' αὐτάρκειαν οὐθὲν μέρος πόλεως, ὥστε ἢ θηρίον ἢ θεός → Whoever is incapable of associating, or has no need to because of self-sufficiency, is no part of a state; so he is either a beast or a god
m (Text replacement - " <span class="bld">" to "<span class="bld">") |
m (Text replacement - "<span class="sense"><span class="bld">A<\/span> (?s)(?!.*<span class="bld">)(.*)(<\/span>)(\n}})" to "$1$3") |
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|Transliteration C=amfietei | |Transliteration C=amfietei | ||
|Beta Code=a)mfietei/ | |Beta Code=a)mfietei/ | ||
|Definition=Adv., (ἔτος) | |Definition=Adv., (ἔτος) [[year by year]], prob. in <span class="title">SIG</span>963.7 (Amorgos, iv B.C.), cf. Suid., <span class="bibl">Eust.1385.1</span>. | ||
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{{pape | {{pape | ||
Revision as of 10:12, 24 August 2022
English (LSJ)
Adv., (ἔτος) year by year, prob. in SIG963.7 (Amorgos, iv B.C.), cf. Suid., Eust.1385.1.
German (Pape)
[Seite 139] = ἀμφίετες, jährlich, VLL.
Greek (Liddell-Scott)
ἀμφιετεί: ἐπίρρ. = τῷ ἑπομ., Σουΐδ., Εὐστ.
Spanish (DGE)
• Alolema(s): ἀμφιέτει Sud.
adv. anualmente, IG 12(7).62.7 (cj. Keil) (Amorgos IV a.C.), Eust.1385.1
•ἐν αὐτῷ τῷ ἔτει Sud.
