βραγχαλέος: Difference between revisions
From LSJ
Ὁ δὲ μὴ δυνάμενος κοινωνεῖν ἢ μηδὲν δεόμενος δι' αὐτάρκειαν οὐθὲν μέρος πόλεως, ὥστε ἢ θηρίον ἢ θεός → Whoever is incapable of associating, or has no need to because of self-sufficiency, is no part of a state; so he is either a beast or a god
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|Transliteration C=vragchaleos | |Transliteration C=vragchaleos | ||
|Beta Code=bragxale/os | |Beta Code=bragxale/os | ||
|Definition=α, ον, (βράγχος) | |Definition=α, ον, ([[βράγχος]]) [[hoarse]], Hp.''Acut.''(Sp.)55. | ||
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{{DGE | |||
|dgtxt=-ον medic. [[que padece ronquera]] Hp.<i>Acut.(Sp.)</i> 55. | |||
}} | }} | ||
{{pape | {{pape | ||
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{{ls | {{ls | ||
|lstext='''βραγχαλέος''': -α, -ον, ([[βράγχος]]) βραγχνός, Ἰππ. 405. 50. | |lstext='''βραγχαλέος''': -α, -ον, ([[βράγχος]]) βραγχνός, Ἰππ. 405. 50. | ||
}} | }} | ||
{{grml | {{grml | ||
|mltxt=[[βραγχαλέος]], -α, -ον (Α)<br />[[βραχνός]].<br />[<b><span style="color: brown;">ΕΤΥΜΟΛ.</span></b> <span style="color: red;"><</span> [[βράγχος]] <span style="color: red;">+</span> -<i>αλέος</i> ( | |mltxt=[[βραγχαλέος]], -α, -ον (Α)<br />[[βραχνός]].<br />[<b><span style="color: brown;">ΕΤΥΜΟΛ.</span></b> <span style="color: red;"><</span> [[βράγχος]] <span style="color: red;">+</span> -<i>αλέος</i> ([[πρβλ]]. [[αργαλέος]], [[κερδαλέος]])]. | ||
}} | }} | ||
{{elnl | {{elnl | ||
|elnltext=[[βραγχαλέος]] -η -ον [[βράγχος]] hees. Hp. | |elnltext=[[βραγχαλέος]] -η -ον [[βράγχος]] hees. Hp. | ||
}} | }} | ||
Latest revision as of 12:13, 25 August 2023
English (LSJ)
α, ον, (βράγχος) hoarse, Hp.Acut.(Sp.)55.
Spanish (DGE)
-ον medic. que padece ronquera Hp.Acut.(Sp.) 55.
German (Pape)
[Seite 460] heiser, Hippocr.
Greek (Liddell-Scott)
βραγχαλέος: -α, -ον, (βράγχος) βραγχνός, Ἰππ. 405. 50.
Greek Monolingual
βραγχαλέος, -α, -ον (Α)
βραχνός.
[ΕΤΥΜΟΛ. < βράγχος + -αλέος (πρβλ. αργαλέος, κερδαλέος)].
Dutch (Woordenboekgrieks.nl)
βραγχαλέος -η -ον βράγχος hees. Hp.
